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0.3x^2=0.1=0.5x
We move all terms to the left:
0.3x^2-(0.1)=0
We add all the numbers together, and all the variables
0.3x^2-0.1=0
a = 0.3; b = 0; c = -0.1;
Δ = b2-4ac
Δ = 02-4·0.3·(-0.1)
Δ = 0.12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.12}}{2*0.3}=\frac{0-\sqrt{0.12}}{0.6} =-\frac{\sqrt{}}{0.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.12}}{2*0.3}=\frac{0+\sqrt{0.12}}{0.6} =\frac{\sqrt{}}{0.6} $
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